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objdump -M intel -d basic | grep -A 15 main.: main() Here, we're disassembling the ‘basic' program, specifying Intel syntax, and piping the output to grep, where we want the next Why does Ubuntu 16.04 installation create an extended partition besides the swap? Best Regards, Anthony Seely If my reply answers your question please click on the green button "Verify Answer". The best way to figure out what that is would be to look at how the stack frame is laid out.

asked 1 year ago viewed 740 times active 11 months ago Upcoming Events 2016 Community Moderator Election ends in 5 days Blog How We Make Money at Stack Overflow: 2016 Edition The BIOS picks somewhere in RAM to set up the stack and loads and executes the first sector of the first bootable drive. So, it is loading the value of *ptr, (brackets mean ‘actual data at location in memory', remember?), into the EAX register. Thanks. http://superuser.com/questions/988473/why-is-the-first-bios-instruction-located-at-0xfffffff0-top-of-ram

0xfffffff0 Netmask

Track 0 is the outermost on the magnetic plate, and sector 1, the first sector, has a special purpose. Reply Cancel Cancel Reply Suggest as Answer Use rich formatting Guru 60355 points Anthony F. it did take a bit of time but got there! :) –gumchew Jul 5 '14 at 18:19 Updated with an example. –Mike DeSimone Jul 5 '14 at 18:23

Seely: Sorry this may only be available through CCS. The BIOS code is located at top of that 1MB. When main() called func() it passed argv[1] as a parameter. Would this be considered as plagiarism?

Reply Cancel Cancel Reply Suggest as Answer Use rich formatting Guru 60355 points Anthony F. 0xfffffff0 To Decimal Thus logical FFFF:FFF0 is physical (1)0FFE0 (where leading 1 is present if A20 is enabled). –Ruslan Oct 19 '15 at 9:58 6 @kasperd There's a hack in place - the Tracks are numbered, and every track is divided into a number (usually 64) of sectors. Seely May 31, 2016 6:46 PM Sarah, Do you have the option 'system reset on connect' set? (it's on the Flash tab of the Debug Properties).

Storing passwords in access-restricted Google spreadsheets? 5 Favorite Letters Would the Ancient One have defended the Earth from a Chitauri invasion in the Avengers absence? Now since we have 64 bits with compatibility to 32 bits and 32 bits to 16 bits, the hardware couild have been improved but the method stays. But this is only a mapping of the address space - the address is mapped directly into the BIOS ROM chip (yes, this means you don't get access to the full Best Regards, Anthony Seely If my reply answers your question please click on the green button "Verify Answer".

0xfffffff0 To Decimal

The instruction pointer register (also known as the Program Counter) points to code to be executed by the processor. More hints So, that wraps up part two of the series. 0xfffffff0 Netmask What does the letter 'u' mean in /dev/urandom? Hex To Decimal Anyway, thank you!

The locker problem - why squares? As you can see, EBP+12 contains the function parameters that we are passing in from the command line. Subnet Mask Table Ads ---------------------------------------------------------- Subnet Mask: 255.255.255.0 Hex Mask: 0xffffff00 Subnet Bits: 24 Host Bits: 8 Number of Subnets: 1 Hosts per Subnet: 254 Network Address IP Range Broadcast Address First, let's once again post our source code, just for reference purposes: #include void func(char *ptr) { char buf[10]; printf("copy %d bytes of data to buf\n", strlen(ptr)); strcpy(buf, ptr); } Bios

Hot Network Questions Why is the natural log of infinity, divided by infinity, equal to infinity over infinity? So, two things here, what is now pointed to by ESP is the string "copy %d bytes of data to buf\n", and what is in ESP+4 is the value going into Of course, starting with at least the 80286, interrupt vectors could be moved to a different starting location other than 0, but modern 64-bit x86 CPUs still boot up in 8086 Are there eighteen or twenty bars in my castle?

Finally, lines 12-14 are basically clean up: 12. 80484e1: b8 00 00 00 00 mov eax,0x0 13. 80484e6: c9 leave 14. 80484e7: c3 ret In the first, it The first pushes EBP, the base pointer, onto the stack. Is it ethical to offer female candidates a higher wage to achieve a more diverse work environment?

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Now, I'm guessing the value we get out of strlen() is headed for printf() to fill in the %d, don't you? Each processor family has its own characteristics. –Nick T Oct 20 '15 at 14:20 1 @imallett I like how you decide to complain about it here rather than asking the I set that option, "System Reset on Connect" in Debug properties | Flash, and I am able to debug. North by North by North by South East How do you combine the elements in Sheldon's T-shirt?

func(argv[1]); 5. 804848d: 89 04 24 mov DWORD PTR [esp],eax Here we see it setting up to do something with this data again, as Line 5 copies the contents of This is carving out space for ‘buf'. Well, there's a trick to it - the 12 high bits of the address are set until you execute your first long jump, giving you access to the high address space up vote 5 down vote favorite 1 When I disassemble a main() in gdb it retuns this result: 0x0804854c <+0>: push ebp 0x0804854d <+1>: mov ebp,esp 0x0804854f <+3>: and esp,0xfffffff0 0x08048552

But it reads only from an address which can be divided by 16: 0x0, 0x10, 0x20,.... Uniflash will not erase, while CCS will not debug. This will simplify things, and allow us to walk through a simple stack based buffer overflow in the 3rd blog post of our series. I tried turning off the unit and my desktop, then restarting to no avail.

So starting from 0 and working up made sense for those (because no system in 1978 when the 8086 was invented would have 4Gbytes of RAM - so expecting RAM to Funky behaviour of derivative Mountainering with 6 y.o. Sure, there's segments, so you have 20-bit address space, but that still isn't good enough. If N is a power of 2, it also means that all the byte addresses that store the entire value are exactly the same except for the lowest-order log2(N) bits.

Join them; it only takes a minute: Sign up What is `and esp,0xfffffff0`? Now, you might be thinking - how does a 16-bit real mode access the address 0xFFFFFFF0? While newer architectures complicate things, historically a machine would on each memory cycle output the desired address on 20 to 32 wires (depending upon the architecture, with some special tricks to Sarah Expert 1650 points Sarah Weinberger May 31, 2016 6:12 PM Reply Cancel Cancel Reply Suggest as Answer Use rich formatting All Responses Answers Only Guru 60355 points Anthony F.

At EBP+8 (8 bytes ‘down' the stack from EBP) is the ‘ptr' pointer variable. How to show the dropdown attibute value using getData() method in magento 2? This has the effect of rounding the stack pointer down to the nearest multiple of 16.